SOLUTION: The revenue function for a new plasma television is given by R(p) = 900p-0.1p^2 What price, p, should be charged to maximize revenue? What is the maximum re

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: The revenue function for a new plasma television is given by R(p) = 900p-0.1p^2 What price, p, should be charged to maximize revenue? What is the maximum re      Log On


   

Question 1055223: The revenue function for a new plasma television is given by R(p) = 900p-0.1p^2
What price, p, should be charged to maximize revenue? What is the maximum revenue?

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Convert the revenue function to vertex form,
R%28p%29=-0.1p%5E2%2B900p
R%28p%29=-0.1%28p%5E2-9000p%29
R%28p%29=-0.1%28p%5E2-9000p%2B4500%5E2%29%2B0.1%284500%29%5E2
R%28p%29=-0.1%28p-4500%29%5E2%2B2025000
So the R%5Bmax%5D=2025000 occurs when p=4500.