Question 1055181: the equation is x squared plus y squared minus 2 x minus 4 y minus 20 equals 0x2+y2−2x−4y−20=0, find the center, radius, and intercepts
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! x2+y2−2x−4y−20=0 rewrite;
x^2-2x+ y^2-4y=20
complete the square
x^2-2x+1+y^2-4y+4=25, adding the +1 and the +4 to both sides
(x-1)^2+(y-2)^2=25
That is a circle with center (1,2) and radius sqrt (25)=5
When x=0, (y-2)^2=24
y-2=+/-2sqrt(6)
y=2+/-2sqrt(6); numerically, this is (0,-2.90),(0,6.90)
y=0
(x-1)^2=21
x=1+/-sqrt (21); numerically, this is (-3.58,0),(5.58,0)
|
|
|
