SOLUTION: find a equation of the line that satisfies the given conditons through (1/2,-2/5): perpendicular to the line 3x-6y=1 this is what i got but it isnt coming right on the computer

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Question 1054613: find a equation of the line that satisfies the given conditons through (1/2,-2/5): perpendicular to the line 3x-6y=1
this is what i got but it isnt coming right on the computer for homework
y=-2/1x-1/5
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+3x+-+6y+=+1+
put into slope-intercept form
+6y+=+3x+-+1+
+y+=+%283%2F6%29%2Ax+-+1+
+y+=+%281%2F2%29%2Ax+-+1+
----------------------
Any line perpendicular to this line has
slope = +-1%2Fm+=+-1%2F%28%281%2F2%29%29++
slope = +-2+
---------------------
( 1/2, -2/5 )
Use the general point-slope formula
+%28%28+y+-%28-2%2F5%29+%29%29+%2F+%28%28+x+-+1%2F2+%29%29+=+-2+
+%28%28+y+%2B+2%2F5+%29%29+%2F+%28%28+x+-+1%2F2+%29%29+=+-2+
+y+%2B+2%2F5+=+-2%2A%28+x+-+1%2F2+%29+
+y+%2B+2%2F5+=+-2x+%2B+1+
+y+=+-2x+%2B+5%2F5+-+2%2F5+
+y+=+-2x+%2B+3%2F5+
------------------------
check:
does it go through ( 1/2, -2/5 ) ?
+y+=+-2x+%2B+3%2F5+
+-2%2F5+=+-2%2A%281%2F2%29+%2B+3%2F5+
+-2%2F5+=+-1+%2B+3%2F5+
+-2%2F5+=+-5%2F5+%2B+3%2F5+
+-2%2F5+=+-2%2F5+
OK