SOLUTION: 4x^2=2x+7

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Question 1050260: 4x^2=2x+7
Answer by addingup(3677) About Me  (Show Source):
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4x^2=2x+7
4x^2-2x-7 = 0
x^2-x/2-7/4 = 0
x^2-x/2 = 7/4
Add 1/16 to both sides:
x^2-x/2+1/16 = 29/16
(x-1/4)^2 = 29/16
x-1/4 = sqrt(29)/4 or x-1/4 = -sqrt(29)/4
x = 1/4+sqrt(29)/4 or x = 1/4-sqrt(29)/4