SOLUTION: The length of a rectangle is 6 ft more than its width. The perimeter of the rectangle is 68 ft. What are the dimensions of the rectangle? Let w represent the width of the rectan

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Question 1049378: The length of a rectangle is 6 ft more than its width. The perimeter of the rectangle is 68 ft. What are the dimensions of the rectangle?
Let w represent the width of the rectangle.
Found 2 solutions by ikleyn, hussamuddin:
Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
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The length of a rectangle is 6 ft more than its width. The perimeter of the rectangle is 68 ft. What are the dimensions of the rectangle?
Let w represent the width of the rectangle.
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Let W represents the width of the rectangle.
Then its length is W+6.

Then the perimeter is 2W + 2(W+6).

Then for the perimeter you have an equation

2W + 2W + 12 = 68.

4W = 68 - 12,

4W = 56,

W = 56%2F4 = 14.

Answer.  The width is 14 ft, the length is 20 ft.

For many other similar solved problems see the lessons
    - Solved problems on the perimeter and side lengths of a triangle
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in this site.


Answer by hussamuddin(51) About Me  (Show Source):