SOLUTION: The length of a rectangle is 6 ft more than its width. The perimeter of the rectangle is 68 ft. What are the dimensions of the rectangle?
Let w represent the width of the rectan
Question 1049378: The length of a rectangle is 6 ft more than its width. The perimeter of the rectangle is 68 ft. What are the dimensions of the rectangle?
Let w represent the width of the rectangle. Found 2 solutions by ikleyn, hussamuddin:Answer by ikleyn(52776) (Show Source):
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The length of a rectangle is 6 ft more than its width. The perimeter of the rectangle is 68 ft. What are the dimensions of the rectangle?
Let w represent the width of the rectangle.
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Let W represents the width of the rectangle.
Then its length is W+6.
Then the perimeter is 2W + 2(W+6).
Then for the perimeter you have an equation
2W + 2W + 12 = 68.
4W = 68 - 12,
4W = 56,
W = = 14.
Answer. The width is 14 ft, the length is 20 ft.