SOLUTION: Could you help me solve ??
The cost of a can of Coca-Cola on January 1, 1960 , was 10 cents. The function {{{C(t)=0.10e^(0.0576t)}}} gives the cost of a can of Coca-Cola, C(t),
Question 1042813: Could you help me solve ??
The cost of a can of Coca-Cola on January 1, 1960 , was 10 cents. The function gives the cost of a can of Coca-Cola, C(t), t years after that.
a.) How much did a can of Coca Cola cost in 1975 (round to nearest penny)?
b.) In what year will a can of Coca-Cola cost $1.00 (round to nearest whole year).
c.) How much does a can of Coca-Cola cost in 2045 ?
Thank you so much !! Found 2 solutions by stanbon, Edwin McCravy:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The cost of a can of Coca-Cola on January 1, 1960 , was 10 cents. The function C(t)=0.10e^(0.0576t) gives the cost of a can of Coca-Cola, C(t), t years after that.
a.) How much does a can of Coca Cola cost in 1975 (round to nearest penny)?
# of years 60 to 75 = 15
C(15) = 0.10*e^(0.0576*15) = 0.10*2.3726 = 0.237 = 24 cents if rounded up
------------------------------------------
b.) In what year will a can of Coca-Cola cost $1.00 (round to nearest whole year).
Solve for "t"
1 = 0.10*e^(0.0576t)
e^(0.0576t) = 10
Take the natural log of both sides to get:
0.0576t = 2.3026
t = 40 if rounded up
Ans: 1960 + 40 = year 2000
--------------------------------
c.) How much does a can of Coca-Cola cost in 2045 ?
1960 to 2045 = 85 years
C(85) = 0.10*e^(0.0576*85)
I'll leave that calculation to you.
Cheers
Stan H.
-----------
(