SOLUTION: Write the equation of the quadratic function with roots -9 and and -3 and a vertex at (-6, -1) Help please!

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Question 1042755: Write the equation of the quadratic function with roots -9 and and -3 and a vertex at (-6, -1)
Help please!

Answer by ikleyn(52777) About Me  (Show Source):
You can put this solution on YOUR website!
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Write the equation of the quadratic function with roots -9 and and -3 and a vertex at (-6, -1)
Help please!
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I know (and you should know it) that this function has a form 

f(x) = a*(x-(-9)*(x-(-3)) = a*(x+9)*(x+3),

where "a" is a real constant.

To determine this constant, I will calculate the function f(x) at the point x = -6, where the vertex is. It is

f(-6) = a*(-6 +9)*(-6+3) = a*3*(-3) = -9a.

Thus, I must find the value of "a" from this equation: 

f(-6) = -1,  which becomes  -9a = -1.

Hence,  a = %28-1%29%2F%28-9%29 = 1%2F9.

Answer.  The function under the question is f(x) = %281%2F9%29%2A%28x%2B9%29%2A%28x%2B3%29.

You may open parentheses if you need.