Question 103811This question is from textbook Intermediate Algebra
: Hello Tutors,
For some reason I can not figure these things out! I know that the Quadratic Formula is:
x = -b±√b2 – 4ac / 2a
But I can't get plugging the problem x^2 - 3x = 7x -2 into the formula and solve. Can someone please help?????
Further directions from my professor are as follows:
Make sure that your work is demonstrating the solving method given in the instructions. Use the Insert and Symbols menus in Word to present the radical √ and plus/minus ± symbols. Remember that radicands must be enclosed within [ ]. Typing your work vertically is preferred but optional. If you choose to type horizontally, make sure you are appropriately using grouping symbols.
This question is from textbook Intermediate Algebra
Answer by ptaylor(2198)   (Show Source):
You can put this solution on YOUR website!
FIRST OF ALL, YOU NEED TO USE GROUPING SYMBOLS AS YOUR PROFESSOR SUGGESTS. I HAVE RE-WRITTEN THE FORMULA BELOW USING GROUPING SYMBOLS TO CLARIFY THE OPERATIONS THAT ARE REQUIRED:
x = {-b±√[b2 – 4ac]} / 2a
SECONDLY, YOU NEED TO GET THE QUADRATIC INTO STANDARD FORM:
x^2 - 3x = 7x -2 SUBTRACT 7X FROM AND ADD 2 TO BOTH SIDES
x^2-3x-7x+2=7x-7x-2+2 COLLECT LIKE TERMS
x^2-10x+2=0---QUADRATIC IN STANDARD FORM (AX^2+BX+C=0)
FROM HERE ON OUT IT'S JUST A MATTER OF PLUGGING IN NUMBERS AND FOLLOWING YOUR PROFESSOR'S INSTRUCTIONS. YOU SHOULD BE ABLE TO HANDLE IT.
Hope this helps----ptaylor
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