SOLUTION: Please help me solve. The length of a rectangle is 1 cm more than 2 times its width. If the area of the rectangle is 76 cm^2, find the dimensions of the rectangle to the neares

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Please help me solve. The length of a rectangle is 1 cm more than 2 times its width. If the area of the rectangle is 76 cm^2, find the dimensions of the rectangle to the neares      Log On


   

Question 103586: Please help me solve.
The length of a rectangle is 1 cm more than 2 times its width. If the area of the rectangle is 76 cm^2, find the dimensions of the rectangle to the nearest thousandth.
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
let x=width so 2x+1=length ... area=x(2x+1) ... 76=2x^2+x

2x^2+x-76=0 ... x=%28-1+%2B-+sqrt%281-%284%29%282%29%28-76%29%29%29%2F%282%282%29%29