SOLUTION: What is the equation of the quadratic function, in vertex form, if the vertex is at (3,5) and has a leading coefficient of 2? options are a.2(x+3)^2+5 b.2(x+3)^2-5 c.2(x-3)^2+5

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: What is the equation of the quadratic function, in vertex form, if the vertex is at (3,5) and has a leading coefficient of 2? options are a.2(x+3)^2+5 b.2(x+3)^2-5 c.2(x-3)^2+5       Log On


   

Question 1034241: What is the equation of the quadratic function, in vertex form, if the vertex is at (3,5) and has a leading coefficient of 2?
options are a.2(x+3)^2+5 b.2(x+3)^2-5 c.2(x-3)^2+5 d.2(x-3)^2-5
i need to show work so help me out here
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
What is the equation of the quadratic function, in vertex form, if the vertex is at (3,5) and has a leading coefficient of 2?

Use the standard form and solve whatever is left not plainly known.
y=a%28x-h%29%5E2%2Bk------format for standard form, vertex (h,k), lead coefficient a.

Just plug-in what is given.