SOLUTION: Can anyone tell me if I did this correctly? 3/x + 2 + x/x^2-4 This is what I did. I took the x^2 - 4 and changed it to (x+2)(x-2) and then crossed out both (x + 2) which

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Can anyone tell me if I did this correctly? 3/x + 2 + x/x^2-4 This is what I did. I took the x^2 - 4 and changed it to (x+2)(x-2) and then crossed out both (x + 2) which       Log On


   



Question 10333: Can anyone tell me if I did this correctly?

3/x + 2 + x/x^2-4

This is what I did. I took the x^2 - 4 and changed it to (x+2)(x-2) and then crossed out both (x + 2) which left me with this answer:

3x/x-2

Is this correct? Thanks for your help. I appreciate it.

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
You are correct to factor the second denominator.
3%2F%28x+%2B+2%29+%2B+x%2F%28%28x-2%29%28x%2B2%29+%29

Next, since this is an addition problem, you must find a common denominator, which is (x-2)(x+2). The second fraction already has the common denominator, so it is good to go!! However, the first fraction is missing something. It's missing a factor of (x-2). So you have to multiply numerator and denominator of the first fraction by (x+2). It looks like this:
%283%2F%28x+%2B+2%29%29%2A%28%28x-2%29%2F%28x-2%29%29+%2B+x%2F%28%28x-2%29%28x%2B2%29+%29

Now, put down the common denominator for the denominator of your answer, and for the numerator of your answer, you have to add the numerators of the two fractions:
%283x-6+%2B+x%29%2F%28%28x-2%29%28x%2B2%29+%29

Combine like terms in the numerator:
%284x-6+%29%2F%28%28x-2%29%28x%2B2%29+%29

You might try to factor the numerator, but it doesn't reduce, so either the previous answer or the factored form is acceptable:
%282%282x-3%29%29%2F%28%28x-2%29%28x%2B2%29+%29

R^2 at SCC