SOLUTION: Student council is selling chocolate bars as a fundraiser. The revenue R, in thousands of dollars, can be modeled by the function R = -25x^2 + 100x + 1500, where x is the number of

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Question 1032508: Student council is selling chocolate bars as a fundraiser. The revenue R, in thousands of dollars, can be modeled by the function R = -25x^2 + 100x + 1500, where x is the number of chocolate bars sold in hundreds. How many cases must the student council sell to maximize their revenue?
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Found 3 solutions by ikleyn, Newb, MathTherapy:
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
Student council is selling chocolate bars as a fundraiser. The revenue R, in thousands of dollars, can be modeled by
the function R = -25x^2 + 100x + 1500, where x is the number of chocolate bars sold in hundreds.
How many cases must the student council sell to maximize their revenue?
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R(x) = -25x%5E2+%2B+100x+%2B+1500 = -%285x-10%29%5E2+%2B+100+%2B+1500 = -%285x-10%29%5E2%2B1600.

The function R(x) has the maximum equal to 1600 at x = 2.


Answer by Newb(4) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, fixed :)
R+=+-25x%5E2+%2B+100x+%2B+1500
Thanks

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Student council is selling chocolate bars as a fundraiser. The revenue R, in thousands of dollars, can be modelled by the function R = -25^2 + 100x + 1500, where x is the number of chocolate bars sold in hundreds. How many cases must the student council sell to maximize their revenue?
Thanks
Maximum profit occurs when x+=+-+b%2F%282a%29, which is: highlight_green%28matrix%281%2C2%2C+200%2C+bars%29%29. Don't know about CASES because you never stated number of bars in each case.