SOLUTION: A ball is thrown upward with an initial velocity of 64 feet/ sec. using h(t)= 64 t-16 t where h(t) is the height of the ball (feet) at any time second. find the maximum height

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Question 1030778: A ball is thrown upward with an initial velocity of 64 feet/ sec. using h(t)= 64 t-16 t where h(t) is the height of the ball (feet) at any time second.
find the maximum height the ball will reach ?
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
I think you mean
h%28t%29+=+64t+-+16t%5E2
It reaches its maximum height when v = 0. That occurs when t = 2 seconds. We know that because g = -32 feet/sec/sec.
Anyway, at t = 2,
h%282%29+=+64%2A2+-+16%2A2%5E2+=+128+-+64+=+64 feet