SOLUTION: the length of a rectangle is represented by x+7 and the width is represented by x+1. If the area of the rectangle is 65 square feet, find the perimeter of this rectangle.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: the length of a rectangle is represented by x+7 and the width is represented by x+1. If the area of the rectangle is 65 square feet, find the perimeter of this rectangle.      Log On


   

Question 1025580: the length of a rectangle is represented by x+7 and the width is represented by x+1. If the area of the rectangle is 65 square feet, find the perimeter of this rectangle.
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Length = (x+7)
width = (x+1)
Area = L * W
(x+7)(x+1) =65
x%5E2%2B8x%2B7+=65
x%5E2%2B8x+-58=0

y=1x2+8x−58 discriminant=b2−4(a)(c)=82−4(1)(−58)=296 ( 2 real solutions )


−b± sqrt(b2−4(a)(c))/√2(a)

−8±82−4(1)(−58)/2(1)
−8±296/2
=−8±4×74 /2
=−8±274 /2
=−4±174
=−4±174


x=4.602325267042627 x=−12.602325267042626
ignore negative
x=4.6
length = 11.6 & width = 5.6