SOLUTION: Find the area of the region enclosed by the graph of the equation x^2 + y^2 = 4x + 6y+13.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Find the area of the region enclosed by the graph of the equation x^2 + y^2 = 4x + 6y+13.       Log On


   

Question 1025025: Find the area of the region enclosed by the graph of the equation x^2 + y^2 = 4x + 6y+13.
Answer by Alan3354(69443) About Me  (Show Source):
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Find the area of the region enclosed by the graph of the equation x^2 + y^2 = 4x + 6y+13.
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x^2 + y^2 = 4x + 6y+13.
x^2-4x + y^2-6y = 13.
Complete the square for x & y.
x^2-4x+4 + y^2-6y+9 = 13+4+9 = 26
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r^2 = 26
Area+=+pi%2Ar%5E2+=+26pi