SOLUTION: Find the area of the region enclosed by the graph of the equation x^2 + y^2 = 4x + 6y+13.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Find the area of the region enclosed by the graph of the equation x^2 + y^2 = 4x + 6y+13.      Log On


   

Question 1024597: Find the area of the region enclosed by the graph of the equation x^2 + y^2 = 4x + 6y+13.
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
The graph for the equation is a circle. Complete the squares on the general form to put into standard form, and identify the radius. Use pi%2Ar%5E2 for the area.

Follow instructions for the solution.
Put the given equation into general form.
Complete the Squares for the x and the y.
Use that to put the equation into STANDARD FORM.
Read the value of the radius from the finished standard form equation.
Now, compute the area, according to pi%2Ar%5E2.