SOLUTION: 2 numbers whose sum is 10 and the sum of their squares is a minimum. If x is the first number, express the minimum as a function of x and find the numbers.

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Question 1013376: 2 numbers whose sum is 10 and the sum of their squares is a minimum. If x is the first number, express the minimum as a function of x and find the numbers.
Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
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2 numbers whose sum is 10 and the sum of their squares is a minimum.
If x is the first number, express the minimum as a function of x and find the numbers.
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Answer. The numbers are 5 and 5.

Proof


Let x be one number, then the other is 10-x.


The sum of their squares is 


x%5E2+%2B+%2810-x%29%5E2 = x%5E2+%2B+100+-+20x+%2B+x%5E2 = 2x%5E2+-+20x+%2B+100 = 2%2A%28x%5E2+-+10x+%2B+50%29 = 2%2A%28x-5%29%5E2+%2B+50.

One can see that this quadratic function has the minimum at x = 5, and this minimum is equal to 50.

Thus we proved that one number, which gives the maximum, is 5.

Then the other number is 5 also.