SOLUTION: The voltage in a circuit is decaying according to the function V(t) = V0e^-0.48t, where V0 is the starting voltage, t is the time in seconds and V(t) is the voltage after t seconds

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Question 1010230: The voltage in a circuit is decaying according to the function V(t) = V0e^-0.48t, where V0 is the starting voltage, t is the time in seconds and V(t) is the voltage after t seconds. If the starting voltage is 6 volts, what will be the voltage after 2.6 seconds?
Round your answer to the nearest hundredth of a volt
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
Starting from
V(t) = V0e^-0.48t
we plug in to find
V(2.6) = 6e^(-.48*2.6) = 1.72 volts