SOLUTION: What are the zeroes of y=x^2+2x-8

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Question 1009942: What are the zeroes of y=x^2+2x-8
Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
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What are the zeroes of y=x^2+2x-8?
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Factor the left side:

x%5E2%2B2x-8 = (x+4)*(x-2).

Now find zeros: x = -4 and x = 2.