SOLUTION: the function for object dropped from a height where t is the time in seconds, h is the height in feet at time t, and h is the initial height h(t)=-16t^2+h , height is 5

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Question 1009336: the function for object dropped from a height where t is the time in seconds, h is the height in feet at time t, and h is the initial height
h(t)=-16t^2+h , height is 50ft I need to know how to figure out how
long it would take to fall to the ground
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
h(t)=-16t^2+h , height is 50ft I need to know how to figure out how
long it would take to fall to the ground
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When it hits the ground its height is zero.
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Solve::
-16t^2 + 50 = 0
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16t^2 = 50
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t^2 = 50/16
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time = 1.77 seconds
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Cheers,
Stan H.
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