SOLUTION: One square has a side length that is 1 footgreater than that of a smaller square. If the combined area of the two squares is 113 feet. find the length of the side of the smaller sq
Question 1009234: One square has a side length that is 1 footgreater than that of a smaller square. If the combined area of the two squares is 113 feet. find the length of the side of the smaller square. Answer by fractalier(6550) (Show Source):
You can put this solution on YOUR website! Call the side of the smaller square, x.
Thus the larger square has a side of x+1.
Since area is side squared, we have
x^2 + (x+1)^2 = 113
x^2 + x^2 + 2x + 1 = 113
2x^2 + 2x - 112 = 0
x^2 + x - 56 = 0
(x + 8)(x - 7) = 0
X = -8 or x = 7
Can't be negative so you have a side of
7 feet
