SOLUTION: In a city with a population of 70,000 people, the number of people P(t) exposed to a rumor in t hours is given by the function P(t) = 70,000(1 − e^−0.0009t).(Round yo

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: In a city with a population of 70,000 people, the number of people P(t) exposed to a rumor in t hours is given by the function P(t) = 70,000(1 − e^−0.0009t).(Round yo      Log On


   



Question 1006197: In a city with a population of 70,000 people, the number of people P(t) exposed to a rumor in t hours is given by the function
P(t) = 70,000(1 − e^−0.0009t).(Round your answers to the nearest hour.)
(a) Find the number of hours until 10% of the population have heard the rumor.
(b) Find the number of hours until 90% of the population have heard the rumor.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+P%28t%29+=+70000%2A%28+1+-+e%5E%28-.0009t%29+%29+
(a)
When is the ratio +P%28t%29+%2F+70000+=+.1+ ?
+P%28t%29+=+.1%2A70000+
+P%28t%29+=+7000+
+7000+=+70000%2A%28+1+-+e%5E%28-.0009t%29+%29+
+.1+=+1+-+e%5E%28+-.0009t+%29+
+e%5E%28+-.0009t+%29+=+.9+
Take the natural log of both sides
+-.0009t+=+ln%28.9%29+
+-.0009t+=+-.10536+
+t+=+117.07+
In 117.07 hrs, 10% have heard rumor
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Follow the same steps:
+.9+=+1+-+e%5E%28+-.0009t+%29+
+e%5E%28+-.0009t+%29+=+.1+
+-.0009t+=+ln%28.1%29+
+-.0009t+=+-2.3026+
+t+=+2558.43+
In 2558.43 hrs, 90% have heard rumor
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