SOLUTION: Use the method of completing the square to find the standard form of the quadratic function. f(x) = x^2 + 6x − 1 State the vertex and axis of symmetry of the graph of the f

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Question 1003803: Use the method of completing the square to find the standard form of the quadratic function.
f(x) = x^2 + 6x − 1
State the vertex and axis of symmetry of the graph of the function.
y=
axis of symmetry x=
vertex(x, y)=

Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
Use the method of completing the square to find the standard form of the quadratic function.
f(x) = x^2 + 6x − 1
State the vertex and axis of symmetry of the graph of the function.
We want to get it in the form

f%28x%29=a%28x-h%29%5E2%2Bk

where the vertex is (h,k) and the axis of symmetry
is the vertical line whose equation is x=h.

Make sure it's in order of descending powers:

f%28x%29+=+x%5E2+%2B+6x+-+1

Factor out the coefficient of the first two terms.
It's 1 here so this step isn't necessary, but I'll
do it anyway so it'll be in the form f%28x%29=a%28x-h%29%5E2%2Bk

f%28x%29+=+1%28x%5E2+%2B+6x%29+-+1

1.  Multiply the coefficient of x, which is 6, by 1/2, getting 3.
2.  Square the result of step 1, 32=9
3.  Add and subtract that number, that is add + 9 - 9 after the 6x:

f%28x%29+=+1%28x%5E2+%2B+6x%2B9-9%29+-+1

Factor the first three terms:

f%28x%29+=+1%28%28x%2B3%29%28x%2B3%29%5E%22%22-9%29+-+1

If you followed the 3 steps above both factors are the same and
it can be written as the square of a binomial:

f%28x%29+=+1%28%28x%2B3%29%5E2-9%29+-+1

Distribute to remove the outer (large) parentheses, leaving the
square of the binomial intact:

f%28x%29+=+1%28x%2B3%29%5E2-9+-+1

Combine the remaining terms as -10

f%28x%29+=+1%28x%2B3%29%5E2-10

That's in the form 

f%28x%29=a%28x-h%29%5E2%2Bk

where a=1, -h=+3, i.e., h=-3, k=-10

so the vertex is (h,k) = (-3,-10) and the axis of symmetry
is the vertical line whose equation is x=h, or x=-3. 



Edwin