Questions on Algebra: Quadratic Equation answered by real tutors!

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Question 766202: Dear Sir/ Madam,
Good day! kindly help me in answering this mathematical problem:
Prove that if roots of ax^2+bx+c=0 are reciprocals, then a=c
Thank you very much for your help!

Click here to see answer by ramkikk66(644) About Me 
Question 766202: Dear Sir/ Madam,
Good day! kindly help me in answering this mathematical problem:
Prove that if roots of ax^2+bx+c=0 are reciprocals, then a=c
Thank you very much for your help!

Click here to see answer by MathTherapy(10549) About Me 

Question 766224: Dear Sir/ Madam,
A pleasant day! can you please help me with this algebraic problem, I need to solve it using quadratic formula but I got confused. Your help will mean a lot. Thanks so much! the problem is z^2-(3+2i) z+(1+3i)=0
i=√(-1) where i=square root of negative 1 .
z^2-(3+2i) z+(1+3i)=0
i=√(-1)

Click here to see answer by solver91311(24713) About Me 

Question 766252: Dear Sir/ Madam,
I am quite familiar in Quadratic formula but I do not know how to use it when there is a square root or imaginary (i) in it. Please help me in solving this algebraic problem, (this one has a square root)
t^2-2t√(2)+1=0 (that is t squared + 2t square root of 2 +1 = 0). Thank you very much for your help. God bless!

Click here to see answer by lwsshak3(11628) About Me 

Question 766269: Dear Sir/Madam,
Please help me with this equation: [(1)/(2z+i)]+[(1)/(2z-1)]=[(1)/(z+2i)] I know that I will be multiplying the equation by the least common denominator but how will I use the quadratic formula in arriving to the final answer? Thank you very much for your help and kindness.

Click here to see answer by stanbon(75887) About Me 

Question 766262: Dear Sir/Madam,
Sorry if I ask a lot of questions about quadratic formula most particularly those with imaginary. Please help me with this one. Again, many,many thanks for your help.
z^2-iz+2=0 when i = √(-1) ( that is square root of -1)

Click here to see answer by solver91311(24713) About Me 

Question 766327: solve by using quadratic formula. prove answer or correct by checking
(5x+1)^2+13=0
This is my answer can it be simplified further. Thanks
25x^2+10x+14=0
b^2-4ac=(10)^2-4*(25)(14)=100-1400=-1300
x=(-b±√(b^2-4ac))/2a
x=(-(10)±√(-1300))/(2(25))
x=(-10±√(-(2^2 x5^2 x〖13〗^1 ))/(2(25))
1/50(-10±10i√13)

Click here to see answer by josgarithmetic(39613) About Me 

Question 766326: solve by using the quadratic formula and checking solution

x^2-3x+4=0
b^2-4ac=(-3)^2-4*(1)(4)=9-16=-7
x=(-b±√(b^2-4ac))/2a
x=(-(-3)±√(-7))/(2(1))
x=1/2-(3±i√(-7))
(1/2 x(3±ix〖√7〗^2-3x(1/2 x(3x(3±ix√(7))+4=0
Is this correct?

Click here to see answer by josgarithmetic(39613) About Me 

Question 766312: Put the equation in the form ax2 + bx + c = 0. Enter exponents using the caret ( ^ . For example, you would enter 4x2 as 4x^2.
(2x+1)^2-3x=5

Click here to see answer by josgarithmetic(39613) About Me 

Question 766331: x^2+4x+c=0
what value of c does the equation have one real root and what range of value does it have two roots, fo what range of values does the equation have two complex.

Click here to see answer by josgarithmetic(39613) About Me 

Question 766456: fill in the blank make the expression a perfect square v^2 - 6v +?
Click here to see answer by lwsshak3(11628) About Me 

Question 766420: solve the following 27.5 = 12/x
Click here to see answer by Alan3354(69443) About Me 

Question 766465: 15x - 35y + 90
31x + 58
-20a - 12b + 5c
1. move the constant term to the right side of the equation
2. multiply each term in the equation by four times the coefficient of the x to the second power term
3. square the coefficient of the original x term and add it to both sides of the equation
4. take the square root of both sides
5. set the left side of the equation equal to the positive square root of the number on the right side and solve for x
6. set the left side of the equation equal to the negative square root of the number on the right side of the equation and solve for x

Click here to see answer by Alan3354(69443) About Me 

Question 766460: 28x - 140 I have six steps to do this problem
1. move the constant term to the right side of the equation
2. multiply each term in the equation by four times the coefficient of the x to the second power term
3. square the coefficient of the original x term and add it to both sides of the equation
4. take the square root of both sides
5. set the left side of the equation equal to the positive square root of the number on the right side and solve for x
6. set the left side of the equation equal to the negative square root of the number on the right side of the equation and solve for x

Click here to see answer by MathLover1(20849) About Me 

Question 766506: Derive a quadratic equation using: x= [-6 +- (5 sqrt 2)]/ 3
Click here to see answer by reviewermath(1029) About Me 

Question 766524: Given F(x) shown below, complete the equation for the inverse of F(x). If necessary, use the slash mark ( / ) for the division symbol.
F(x) = 4x + 7
F -1(y) = _____

Click here to see answer by pawan kumar rastogi(2) About Me 

Question 766566: to solve by completing the square, what value should be added to both sides of the equation x^2+18x=-1
Click here to see answer by nerdybill(7384) About Me 

Question 766630: one number is equal to the square of another .Find the numbers if both are positive and their sum is 1806
Click here to see answer by MathTherapy(10549) About Me 
Question 766630: one number is equal to the square of another .Find the numbers if both are positive and their sum is 1806
Click here to see answer by Shana-D77(132) About Me 

Question 766811: c)(i) Write the quadratic expression x^2-34x+9 in completed square form
(ii) use the completed square form from part (c) (i) to solve the equation x^2-34x+9=0, leaving your answer in exact (surd) form
(iii) use the completed square form from part (c)(i)to write down the vertex of the parabola y=x^2-34x+9

Click here to see answer by MathLover1(20849) About Me 

Question 766849: 2x+3y=2
4x+2y=-3
what number would you multiply the top equation by to eliminate the x terms?

Click here to see answer by Edwin McCravy(20054) About Me 

Question 766776: Derive a quadratic equation using the following points: (1, -4), (2, -5), (3, -10)
Click here to see answer by tommyt3rd(5050) About Me 

Question 766863: What number is equal to three less than its square?
Please help me and show me the solution if possible with detailed explanation. Thank you!

Click here to see answer by Alan3354(69443) About Me 

Question 766906: twin brothers, Billy and Bobby, can mow their grandparents lawn together in 114 minutes. Billy could mow the lawn by himself 45 minutes less time that it would take Bobby. How long would it take Bobby to mow the lawn by himself?
Click here to see answer by josgarithmetic(39613) About Me 

Question 766905: Meg rowed her boat upstream a distance of 91 mi and then rowed back to the starting point. The total time of the trip was 20 hours. If the rate of the current was 3 mph, find the average speed of the boat relative to the water.
Click here to see answer by mananth(16946) About Me 

Question 767134: Q1

a) Orla and Maeve like to play volleyball once a week. When Maeve serves, the tractory of the ball aftre she hits it can be modelled by the quadratic equation
y=-1/8x^2+9/8x+5/4


where y reprsents the height in metres of the ball above the ground , and x reprsents the horizontal distnace of the ball from the position where it was struck by Maeve , measured in metres. Assume that the surface of the volleyball court is horizontal


a) the graph of y=-1/8x^2+9/8x+5/4 is a parabola

(i) is the parabola a u-shaped or a n-shaped? How can you tell this from the equation?


(ii)Use algebra to find the x-intercepts and y-intercepts


(iii) find the equation of the axis of symmetry , explaining your method. Use this information to find the coordinates of the vertex, giving your answers to one decimal place


(iv) Provide a sketch of the parabola


Q1 (b)in this part of the question you are asked to consider the trajectory of the ball modelled by the equation y=-1/8x^2+9/8x+5/4, in the conjunction with the results that you found in part (a)


(i) Find the length of the ball when it is 4 metres horizontally from the postion where Maeve serves it


(ii) use your answer to part (a)(iii) to find the maximum height reached by the ball


(iii) what does the y-intercept represent in the context of this model?


(iv) Assuming that the ball is not returned ,how far will it be horizontally from when Maeve served itwhen it first lands on the court/ Explain your answer


Q2 A) use the quadratic formula to solve the equation 3p^2+5p-11=0

give your answers to two decimal places


b) this part of the question concerns the the quadratic equation 7x^2-3x-11=0

(i)Find the discriminant of the quadratic expression 7x^2-3x-11


(ii) What does this tell you about the number of solutions of the equation ? explain your answer breifly


(iii) what does this tell you about the graph of y=7x^2-3x-11


Click here to see answer by solver91311(24713) About Me 

Question 767354: Sir/Madam,
A pleasant day! Please help me understand how to solve this problem. Find the value of k so that the equation is:
2x^2+kx-15=0, has one root of 3
Thank you very much for your help!

Click here to see answer by josmiceli(19441) About Me 

Question 767408: Sir/Madam,
A pleasant day! please help me with this problem:
Find the value of k so that the equation 2x^2-kx+8=0 will have imaginary roots .
Thank you very much for helping me!

Click here to see answer by nerdybill(7384) About Me 

Question 767452: Dear Sir/Madam,
Good day! Kindly help me on this problem:
Find the value of k so that the equation 3x^2-4kx+k = 0 will have real roots. Thank you very much for your help!

Click here to see answer by lwsshak3(11628) About Me 
Question 767452: Dear Sir/Madam,
Good day! Kindly help me on this problem:
Find the value of k so that the equation 3x^2-4kx+k = 0 will have real roots. Thank you very much for your help!

Click here to see answer by solver91311(24713) About Me 

Question 767460: Dear Sir/Madam,
Good day! Kindly help me with this problem, I sent almost the same problem but committed an error of tying the wrong value. Here it goes...
Find the value of k so that the equation 3x^2-4kx+k =0 will have real roots. Thank you very much for your help!

Click here to see answer by reviewermath(1029) About Me 

Question 767720: DEar Sir/Madam,
Please help me in solving this problem, I am not much familiar with finding the range of values of k. The problem is: Find the range of values of k so that the equation x^2+2kx+3/4 - k will not intersect the y-axis? Thank you very much for your help!

Click here to see answer by solver91311(24713) About Me 

Question 767753: Dear Sir/Madam,
A pleasant day! Please help me with this problem on quadratic equation:
3x^2-7x+6=k, roots equal to zero. Thank you very much for your help!

Click here to see answer by Alan3354(69443) About Me 
Question 767753: Dear Sir/Madam,
A pleasant day! Please help me with this problem on quadratic equation:
3x^2-7x+6=k, roots equal to zero. Thank you very much for your help!

Click here to see answer by josgarithmetic(39613) About Me 

Question 767699: Dear Sir/Madam,
Kindly help me in finding the value of k so that the equation 2x^2+(4-k)x-17=0, roots numerically equal but opposite in sign.
Thank you for your help!

Click here to see answer by ankor@dixie-net.com(22740) About Me 

Question 767758: the volume of a rectangular chinese box is given by the formula V=LWH The volume of the box shown on the right is 210cu units find the width and lenght
Click here to see answer by Alan3354(69443) About Me 

Question 767757: solve the initial value problem:
please help with this differential equation
%28dy%29%2F%28dx%29%22%22=%22%22%28e%5E%284x%29%2B1%29%2F%28e%5E%284x%29%2B4x%2B4%29 (x>-1) y=1 when x=0

I have y= %281%2F4e%5E%284x%29%29-1%2F4e%5E%28-4x%29%2B2x%5E2%2B4x%2B1 is this correct
thankyou for your time!!!

Click here to see answer by Edwin McCravy(20054) About Me 

Question 767787: Dear Ma'am/ Sir,
Please help me in solving this equation, what are the steps that I should do? Thank you very much for helping me. Here is the question: Find the quadratic equation whose roots are twice the roots of 4x^2+8x-5=0.
Thanks Again!

Click here to see answer by tommyt3rd(5050) About Me 
Question 767787: Dear Ma'am/ Sir,
Please help me in solving this equation, what are the steps that I should do? Thank you very much for helping me. Here is the question: Find the quadratic equation whose roots are twice the roots of 4x^2+8x-5=0.
Thanks Again!

Click here to see answer by reviewermath(1029) About Me 

Question 768012: Find all points on the y-axis that are 6 units from the point (4,-3)
Click here to see answer by reviewermath(1029) About Me 

Question 768170: Use the info provided to write the standard form of each parabola.
1) Vertex (-4,-6). Focus (-4,-49/8)
I'm working on my math summer assignment and I don't remember much about this topic.
Thanks for your help.

Click here to see answer by josgarithmetic(39613) About Me 

Question 768234: Hello,
My question is "the product of two consecutive positive integers is 29 more than their sum, find the integers".
I don't understand what the computer went over, there were additional steps that confused me, like a whole 2 steps about changing "1n" to "n" when n=1n.
n(n+1)=2n+1 then 2n+1+29=2n+30 then subtract 2n and 30 so that the equation is 2(n+1)-2n-30=0 then this is where I got confused. The next step was n*n+n-2n-30 so n^2-1n-30=0 then the answers are 6,-5. Where do the 6 and -5 come from and is that right, they're not both positive, but changing to 5,6 makes sense but I don't know how to check my answer.
Please help and thank you

Click here to see answer by Alan3354(69443) About Me 

Question 767686: -16x^2+80x+5=0 -16x^2+80x+5=110
Click here to see answer by Edwin McCravy(20054) About Me 

Question 768874: Hi to everyone.... I've few questions to ask, first one is
"Can we say the elliptic equation, hyperbolic and parabolic equations as quadratic equation?"
"In a general quadratic equation, the constants a,b and c are real or complex?"
"In the word "Quadratic", Quad means four but quadratic equation deals with highest degree 2, So why its name is quadratic?"
Pliz reply all the questions ASAP...

Click here to see answer by stanbon(75887) About Me 

Question 768904: ok I cant figure this out, I have been very good in math but I am getting stumped on this, the problem is 3x^2 -30x+48=0, and I have to answer it in another equation, I never learned this and am very confused on how or what to do
Click here to see answer by mathslover(157) About Me 

Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 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17551..17595, 17596..17640, 17641..17685, 17686..17730, 17731..17775, 17776..17820, 17821..17865, 17866..17910, 17911..17955, 17956..18000, 18001..18045, 18046..18090, 18091..18135, 18136..18180, 18181..18225, 18226..18270, 18271..18315, 18316..18360, 18361..18405, 18406..18450, 18451..18495, 18496..18540, 18541..18585, 18586..18630, 18631..18675, 18676..18720, 18721..18765, 18766..18810, 18811..18855, 18856..18900, 18901..18945, 18946..18990, 18991..19035, 19036..19080, 19081..19125, 19126..19170, 19171..19215, 19216..19260, 19261..19305, 19306..19350, 19351..19395, 19396..19440, 19441..19485, 19486..19530, 19531..19575, 19576..19620, 19621..19665, 19666..19710, 19711..19755, 19756..19800, 19801..19845, 19846..19890, 19891..19935, 19936..19980, 19981..20025, 20026..20070, 20071..20115, 20116..20160, 20161..20205, 20206..20250, 20251..20295, 20296..20340, 20341..20385, 20386..20430, 20431..20475, 20476..20520, 20521..20565, 20566..20610, 20611..20655, 20656..20700, 20701..20745, 20746..20790, 20791..20835, 20836..20880, 20881..20925, 20926..20970, 20971..21015, 21016..21060, 21061..21105, 21106..21150, 21151..21195, 21196..21240, 21241..21285, 21286..21330, 21331..21375, 21376..21420, 21421..21465, 21466..21510, 21511..21555, 21556..21600, 21601..21645, 21646..21690, 21691..21735, 21736..21780, 21781..21825, 21826..21870, 21871..21915, 21916..21960, 21961..22005, 22006..22050, 22051..22095, 22096..22140, 22141..22185, 22186..22230, 22231..22275, 22276..22320, 22321..22365, 22366..22410, 22411..22455, 22456..22500, 22501..22545, 22546..22590, 22591..22635, 22636..22680, 22681..22725, 22726..22770, 22771..22815, 22816..22860, 22861..22905, 22906..22950, 22951..22995, 22996..23040, 23041..23085, 23086..23130, 23131..23175, 23176..23220, 23221..23265, 23266..23310, 23311..23355, 23356..23400, 23401..23445, 23446..23490, 23491..23535, 23536..23580, 23581..23625, 23626..23670, 23671..23715, 23716..23760, 23761..23805, 23806..23850, 23851..23895, 23896..23940, 23941..23985, 23986..24030, 24031..24075, 24076..24120, 24121..24165, 24166..24210, 24211..24255, 24256..24300, 24301..24345, 24346..24390, 24391..24435, 24436..24480, 24481..24525, 24526..24570, 24571..24615, 24616..24660, 24661..24705, 24706..24750, 24751..24795, 24796..24840, 24841..24885, 24886..24930, 24931..24975, 24976..25020, 25021..25065, 25066..25110, 25111..25155, 25156..25200, 25201..25245, 25246..25290, 25291..25335, 25336..25380, 25381..25425, 25426..25470, 25471..25515, 25516..25560, 25561..25605, 25606..25650, 25651..25695, 25696..25740, 25741..25785, 25786..25830, 25831..25875, 25876..25920, 25921..25965, 25966..26010, 26011..26055, 26056..26100, 26101..26145, 26146..26190, 26191..26235, 26236..26280, 26281..26325, 26326..26370, 26371..26415, 26416..26460, 26461..26505, 26506..26550, 26551..26595, 26596..26640, 26641..26685, 26686..26730, 26731..26775, 26776..26820, 26821..26865, 26866..26910, 26911..26955, 26956..27000, 27001..27045, 27046..27090, 27091..27135, 27136..27180, 27181..27225, 27226..27270, 27271..27315, 27316..27360, 27361..27405, 27406..27450, 27451..27495, 27496..27540, 27541..27585, 27586..27630, 27631..27675, 27676..27720, 27721..27765, 27766..27810, 27811..27855, 27856..27900, 27901..27945, 27946..27990, 27991..28035, 28036..28080, 28081..28125, 28126..28170, 28171..28215, 28216..28260, 28261..28305, 28306..28350, 28351..28395, 28396..28440, 28441..28485, 28486..28530, 28531..28575, 28576..28620, 28621..28665, 28666..28710, 28711..28755, 28756..28800, 28801..28845, 28846..28890, 28891..28935, 28936..28980, 28981..29025, 29026..29070, 29071..29115, 29116..29160, 29161..29205, 29206..29250, 29251..29295, 29296..29340, 29341..29385, 29386..29430, 29431..29475, 29476..29520, 29521..29565, 29566..29610, 29611..29655, 29656..29700, 29701..29745, 29746..29790, 29791..29835, 29836..29880, 29881..29925, 29926..29970, 29971..30015, 30016..30060, 30061..30105, 30106..30150, 30151..30195, 30196..30240