Question 998572: Find in the form y=ax^2+bx+c, the equation of the quadratic whose graph cuts the x-axis at 5, passes thrpugh (2,5) and has axis of symmetry x=1
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find in the form y=ax^2+bx+c, the equation of the quadratic whose graph cuts the x-axis at 5, passes through (2,5) and has axis of symmetry x=1
-----
x-intercept at (5,0) which is 4 to the right of the axis of symmetry.
x-intercept at (-3,0) which is 4 to the left of the axis of symmetry.
---------
Form:: y = a(x-5)(x+3)+c
Using (2,5), solve for "c"::
5 = a(-3)(5)+c
---
Cheers,
Stan H.
|
|
|
