SOLUTION: For what values of k will kx^2+10x-6=0 have no solutions? Thanks!

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Question 978397: For what values of k will kx^2+10x-6=0 have no solutions? Thanks!
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
kx%5E2%2B10x-6=0
So you want to find the values of k for which this has no real solutions.
Remember that there are no real solutions if the discriminant is less than 0. So we have:
b%5E2+-+4ac+%3C+0...since in your case a=k, b=10, and c=-6,we have
100+-4%2Ak%2A25+%3C+0
100+-100k+%3C+0
100%281+-+k%29+%3C+0
1+-+k+%3C+0
1+%3C+k
or
k%3E1
So this equation has no solutions for k%3E1.