SOLUTION: I am dividing Rational expression by another rational expression and am getting stuck. Here is the situation:
the problem: x^2+3x-28/x^2-36 divided by x^2-13x+36/x^2+11x+30
Aft
Question 971728: I am dividing Rational expression by another rational expression and am getting stuck. Here is the situation:
the problem: x^2+3x-28/x^2-36 divided by x^2-13x+36/x^2+11x+30
After inverting the dividend, I followed the steps and ended up with
(x-7)(x-4)/(x-9)(x+4) times (x+6)(x+5)/(x-9)(x-4)
After cancelling out (x-4), I'm stuck.
The answer key has an answer of
(x-7)(x+5)/(x-6)(x-9) How did they get that answer if there is still (x+5) and (x+4) still in the equation? Found 2 solutions by Boreal, MathTherapy:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! x^2+3x-28/x^2-36 ;; This is (x+7) (x-4)/(x+6)(x-6)
x^2-13x+36/x^2+11x+30 ;; This is (x-9)(x-4)/(x+6)(x+5)
Numerator
(x+7) (x-4)/(x+6)(x-6) * (x+6)(x+5)/(x-4)(x-9)
The (x+6) go away and so do the (x-4)
(x+7)/(x-6) * (x+5)/(x+9)
You can cancel an (x+6); also, the first term in the numerator is (x+7), not (x-7)
You can put this solution on YOUR website!
I am dividing Rational expression by another rational expression and am getting stuck. Here is the situation:
the problem: x^2+3x-28/x^2-36 divided by x^2-13x+36/x^2+11x+30
After inverting the dividend, I followed the steps and ended up with
(x-7)(x-4)/(x-9)(x+4) times (x+6)(x+5)/(x-9)(x-4)
After cancelling out (x-4), I'm stuck.
The answer key has an answer of
(x-7)(x+5)/(x-6)(x-9) How did they get that answer if there is still (x+5) and (x+4) still in the equation?
This is how: ------ Factoring numerators and denominators ------ Changing division to multiplication and inverting DIVISOR ----- Canceling numerators and denominators , or
You should be able to determine where you went wrong!!
