Question 971724: I am working on dividing a rational expression with another rational expression and I am having issues. Here is the problem:
x^2+3x-28/x^2-36 divided by x^2-13x+36/x^2-11x+30
Now, I understand that I need to invert the divisor so now thw problem looks like this:
x^2+3x-28/x^2-36 divided by x^2-11x+30/x^2-13x+36
Now, after I've done the steps, I end up with:
(x+7)(x-4)/(x-9)(x+4)times (x-6)(x-5)/(x-9)(x-4)
Now i have the problem. The answer key has the answer as (x-7)(x-4)/(X-6)(X-9)
Since I already inverted the divisor earlier, how does the answer key show (x-6) as a denominator when its a numerator and Where's (x-5)? Im sorry for the long explanation. Help me please!
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39616)   (Show Source):
You can put this solution on YOUR website! You recognized and described the idea in words but then you did not do that with the parts of the expression. Yes, in fact, INVERT the divisor and MULTIPLY.
Answer by MathTherapy(10551)  (Show Source):
You can put this solution on YOUR website!
I am working on dividing a rational expression with another rational expression and I am having issues. Here is the problem:
x^2+3x-28/x^2-36 divided by x^2-13x+36/x^2-11x+30
Now, I understand that I need to invert the divisor so now thw problem looks like this:
x^2+3x-28/x^2-36 divided by x^2-11x+30/x^2-13x+36
Now, after I've done the steps, I end up with:
(x+7)(x-4)/(x-9)(x+4)times (x-6)(x-5)/(x-9)(x-4)
Now i have the problem. The answer key has the answer as (x-7)(x-4)/(X-6)(X-9)
Since I already inverted the divisor earlier, how does the answer key show (x-6) as a denominator when its a numerator and Where's (x-5)? Im sorry for the long explanation. Help me please!
DUPLICATE!!
See your other post!!
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