SOLUTION: These quadratics are killing me. Can you help me with this one? (x+2)(x+3)=(x+7)(x-4) I have multiplied and got x^2+6=X^2-28 but where do I go from here? Should I subtract 6 f

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: These quadratics are killing me. Can you help me with this one? (x+2)(x+3)=(x+7)(x-4) I have multiplied and got x^2+6=X^2-28 but where do I go from here? Should I subtract 6 f      Log On


   

Question 971190: These quadratics are killing me. Can you help me with this one?
(x+2)(x+3)=(x+7)(x-4)
I have multiplied and got x^2+6=X^2-28
but where do I go from here? Should I subtract 6 from both sides or add 28 to each side?
Answer by josgarithmetic(39617) About Me  (Show Source):