SOLUTION: A ball is thrown upward from a height of 15 feet with an initial velocity of 5 ft/s. use the formula h(t) = -16t^2 + 5t + 15 what is the maximum height the maximum height of the ba
Question 969823: A ball is thrown upward from a height of 15 feet with an initial velocity of 5 ft/s. use the formula h(t) = -16t^2 + 5t + 15 what is the maximum height the maximum height of the ball? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! A ball is thrown upward from a height of 15 feet with an initial velocity of 5 ft/s. use the formula h(t) = -16t^2 + 5t + 15 what is the maximum height the maximum height of the ball?
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h(t) = -16t^2 + 5t + 15
complete the square:
h(t) = -16(t^2 - (5/16)t+(25/1024))+25/64 + 960/64
h(t) = -16(t- (5/32))^2)+985/64
This is an equation of a parabola that opens downward with vertex at (5/32,985/64)
maximum height of the ball=985/64≈15.39 ft
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