SOLUTION: what is the factor of the expression 30x^2+63x+27

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Question 917252: what is the factor of the expression
30x^2+63x+27

Found 2 solutions by jim_thompson5910, MathLover1:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

30x%5E2%2B63x%2B27 Start with the given expression.


3%2810x%5E2%2B21x%2B9%29 Factor out the GCF 3.


Now let's try to factor the inner expression 10x%5E2%2B21x%2B9


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Looking at the expression 10x%5E2%2B21x%2B9, we can see that the first coefficient is 10, the second coefficient is 21, and the last term is 9.


Now multiply the first coefficient 10 by the last term 9 to get %2810%29%289%29=90.


Now the question is: what two whole numbers multiply to 90 (the previous product) and add to the second coefficient 21?


To find these two numbers, we need to list all of the factors of 90 (the previous product).


Factors of 90:
1,2,3,5,6,9,10,15,18,30,45,90
-1,-2,-3,-5,-6,-9,-10,-15,-18,-30,-45,-90


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 90.
1*90 = 90
2*45 = 90
3*30 = 90
5*18 = 90
6*15 = 90
9*10 = 90
(-1)*(-90) = 90
(-2)*(-45) = 90
(-3)*(-30) = 90
(-5)*(-18) = 90
(-6)*(-15) = 90
(-9)*(-10) = 90

Now let's add up each pair of factors to see if one pair adds to the middle coefficient 21:


First NumberSecond NumberSum
1901+90=91
2452+45=47
3303+30=33
5185+18=23
6156+15=21
9109+10=19
-1-90-1+(-90)=-91
-2-45-2+(-45)=-47
-3-30-3+(-30)=-33
-5-18-5+(-18)=-23
-6-15-6+(-15)=-21
-9-10-9+(-10)=-19



From the table, we can see that the two numbers 6 and 15 add to 21 (the middle coefficient).


So the two numbers 6 and 15 both multiply to 90 and add to 21


Now replace the middle term 21x with 6x%2B15x. Remember, 6 and 15 add to 21. So this shows us that 6x%2B15x=21x.


10x%5E2%2Bhighlight%286x%2B15x%29%2B9 Replace the second term 21x with 6x%2B15x.


%2810x%5E2%2B6x%29%2B%2815x%2B9%29 Group the terms into two pairs.


2x%285x%2B3%29%2B%2815x%2B9%29 Factor out the GCF 2x from the first group.


2x%285x%2B3%29%2B3%285x%2B3%29 Factor out 3 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%282x%2B3%29%285x%2B3%29 Combine like terms. Or factor out the common term 5x%2B3


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So 3%2810x%5E2%2B21x%2B9%29 then factors further to 3%282x%2B3%29%285x%2B3%29


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Answer:


So 30x%5E2%2B63x%2B27 completely factors to 3%282x%2B3%29%285x%2B3%29.


In other words, 30x%5E2%2B63x%2B27=3%282x%2B3%29%285x%2B3%29.


Note: you can check the answer by expanding 3%282x%2B3%29%285x%2B3%29 to get 30x%5E2%2B63x%2B27 or by graphing the original expression and the answer (the two graphs should be identical).


Let me know if you need more help or if you need me to explain a step in more detail.
Feel free to email me at jim_thompson5910@hotmail.com
or you can visit my website here: http://www.freewebs.com/jimthompson5910/home.html

Thanks,

Jim

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

30x%5E2%2B63x%2B27 ..........factor out 3
3%2810x%5E2%2B21x%2B9%29 ........write 21x as 15x%2B6x
3%2810x%5E2%2B15x%2B6x%2B9%29 ....group
3%28%2810x%5E2%2B15x%29%2B%286x%2B9%29%29
3%285x%282x%2B3%29%2B3%282x%2B3%29%29
3%285x%2B3%29%282x%2B3%29