SOLUTION: Algebraically find the the vertex y=6+x-x^2 I know how to find vertex, i am just confused if c=6 b=x a=-x^2 or do i have to change the equation to make it positive like x^2-x-6

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: Algebraically find the the vertex y=6+x-x^2 I know how to find vertex, i am just confused if c=6 b=x a=-x^2 or do i have to change the equation to make it positive like x^2-x-6      Log On


   

Question 902187: Algebraically find the the vertex
y=6+x-x^2
I know how to find vertex, i am just confused if c=6 b=x a=-x^2 or do i have to change the equation to make it positive like x^2-x-6 instead. Not sure if that makes a difference.
Thanks in advance
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
y = -x^2 + x + 6 |Completing the Square
y = -(x - .5)^2 + 6.25 V(-.5, 6.25) Parabola Opening Downward