SOLUTION: Help! I am stumped. I'm trying to solve this quadratic equation, and I'm not sure if the answer I've come up with is correct. Any help you can give me would be greatly appreciated.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: Help! I am stumped. I'm trying to solve this quadratic equation, and I'm not sure if the answer I've come up with is correct. Any help you can give me would be greatly appreciated.      Log On


   

Question 87735: Help! I am stumped. I'm trying to solve this quadratic equation, and I'm not sure if the answer I've come up with is correct. Any help you can give me would be greatly appreciated.
Original Equation: (x+3)^2 = 5
Answer I've come up with so far: 5+/- sqrt.3
Am I even close to the correct answer?
Thank you again for your help!!

Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
(X+3)^2=5
X^2+6X+9=5
X^2+6X+9-5=0
X^2+6X+4=0
USING THE QUADRATIC EQUATION WE GET:x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
X=(-6+-SQRT[6^2-4*1*4])/2*1
X=(-6+-SQRT[36-16])/2
X=(-6+-SQRT20)/2
X=(-6+-4.47)/2
X=(-6+4.47)/2
X=-1.528/2
X=-.764 ANSWER.
X=(-6-4.47)/2
X=-10.47/2
X=-5.236 ANSWER.