SOLUTION: Solve by completing the square x^2+4x-3=0

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Question 87630: Solve by completing the square
x^2+4x-3=0
Answer by madhujiithcharu@yahoo.co.in(28) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 + 4x - 3 = 0
x = -4 + or - \/ 16-4(1)(-3) / 2
= -4 + or - \/28 / 2
= -4 + or - 2\/7 /2
= -2 + or - \/7
therefore x = -2 + \/7 , x = -2 - \/7