SOLUTION: The hypotenuse of a right triangle is 6cm and one side is 2cm longer than the other. Find the length of each side to the nearest tenth of a centimeter. In this question, you have

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: The hypotenuse of a right triangle is 6cm and one side is 2cm longer than the other. Find the length of each side to the nearest tenth of a centimeter. In this question, you have      Log On


   

Question 871468: The hypotenuse of a right triangle is 6cm and one side is 2cm longer than the other. Find the length of each side to the nearest tenth of a centimeter.
In this question, you have to use quadratic equations. (Grade 10)
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
using Pythagoras theorem
one leg be x
orther leg = x=2
x^2+(x+2)^2=6^2
x^2+x^2+4x+4=36
2x^2+4x+4=36
2x^2+4x-32=0
/2
x^2+2x-16=0

Find the roots of the equation by quadratic formula

a= 1 , b= 2 , c= -16

b^2-4ac= 4 + 64
b^2-4ac= 68
%09sqrt%28%0968%09%29=%098.25%09
x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=( -2 + 8.25 )/ 2
x1= 3.12
x2=%28-b-sqrt%28b%5E2-4ac%29%29%2F%282a%29
x2=( -2 -8.25 ) / 2
x2= -5.12
x= 3.12 OR -5.12