SOLUTION: solve for x, where x is a real number: ((x^4)-1)/(x^3) =0

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Question 779278: solve for x, where x is a real number:
((x^4)-1)/(x^3) =0
Found 2 solutions by oscargut, MathTherapy:
Answer by oscargut(2103) About Me  (Show Source):
You can put this solution on YOUR website!
((x^4)-1)/(x^3) =0
x^4-1 = 0 or x^3 = 0
(x^2-1)(x^2+1)=0 or x^3=0
x^2-1=0 or x = 0
(x-1)(x+1)=0 or x= 0
x = 1, x=-1 or x =0
If you have more questions i can see them if you contact me at: mthman@gmail.com
Thanks

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

solve for x, where x is a real number:
((x^4)-1)/(x^3) =0

When solved x+=+1_or_x+=+-+1_or_x+=+0. However, x+%3C%3E+0 (x CANNOT equal 0), so highlight_green%28x+=+1_or_x+=+-+1%29

You can do the check!!

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