Question 766630: one number is equal to the square of another .Find the numbers if both are positive and their sum is 1806 Found 2 solutions by MathTherapy, Shana-D77:Answer by MathTherapy(10551) (Show Source):
You can put this solution on YOUR website!
one number is equal to the square of another .Find the numbers if both are positive and their sum is 1806
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You can put this solution on YOUR website! "one number is equal to the square of another": y = x^2
"if both are positive and their sum is 1806": y + x = 1806
with substitution:
x^2 + x = 1806
Set to zero:
x^2 + x - 1806 = 0
Factor:
(x + 43)(x - 42) = 0
Solve:
x = -43, x = 42
Since your teacher said the numbers are positive, x must = 42.
If y = x^2, then:
y = 1764
