SOLUTION: solve by using the quadratic formula and checking solution x^2-3x+4=0 b^2-4ac=(-3)^2-4*(1)(4)=9-16=-7 x=(-b±√(b^2-4ac))/2a x=(-(-3)±√(-7))/(2(1)) x=1

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: solve by using the quadratic formula and checking solution x^2-3x+4=0 b^2-4ac=(-3)^2-4*(1)(4)=9-16=-7 x=(-b±√(b^2-4ac))/2a x=(-(-3)±√(-7))/(2(1)) x=1      Log On


   

Question 766326: solve by using the quadratic formula and checking solution

x^2-3x+4=0
b^2-4ac=(-3)^2-4*(1)(4)=9-16=-7
x=(-b±√(b^2-4ac))/2a
x=(-(-3)±√(-7))/(2(1))
x=1/2-(3±i√(-7))
(1/2 x(3±ix〖√7〗^2-3x(1/2 x(3x(3±ix√(7))+4=0
Is this correct?

Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
Just be more careful about how you use text to express your expressions.
The work seems good.

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highlight%28%283%2B-sqrt%28-7%29%29%2F2%29
OR if you prefer,
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OR still further,
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