Question 711590: A ball thrown vertically into the air has its height above ground given by h=-16t^2+112t, where t is in seconds and s is in feet. When will the ball hit the ground?
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! A ball thrown vertically into the air has its height above ground given by h=-16t^2+112t, where t is in seconds and s is in feet. When will the ball hit the ground?
When the ball is on the ground, the height (h) is zero. So, set h to zero and solve for t:
h=-16t^2+112t
0=-16t^2+112t
0=16t^2-112t
0=t^2-7t
0=t(t-7)
.
t = {0, 7}
Throw out the 0 (start) leaving:
t = 7 seconds
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