SOLUTION: If the product of two consecutive odd integers is decreased by one-third the lesser integer, the result is 250. Find the integers.

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Question 66194This question is from textbook merrill algebra two with trigonometry
: If the product of two consecutive odd integers is decreased by one-third the lesser integer, the result is 250. Find the integers.
 This question is from textbook merrill algebra two with trigonometry

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
x(x+2)-x/3=250
(x^2+2x)-x/3=250
(3x^2+6x-x)/3=250
3x^2+5x=750
3x^2+5x-750=0 using the quadratic equation we get
x=(-5+-sqrt[5^5-4*3*-750])/2*3
x=(-5+-sqrt[25+9000])/6
x=(-5+-sqrt9025])/6
x=(-5+-95)/6
x=(-5+95)/6
x=90/6
x=15 solution
x=(-5-95)/6
x=-100/6
x=-16 2/3
proof
15(15+2)-15/3=250
15*17-5=250
255-5=250
250=250