SOLUTION: 2x^2+14x+4=0 I cant seem to find the answer

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: 2x^2+14x+4=0 I cant seem to find the answer       Log On


   

Question 649368: 2x^2+14x+4=0 I cant seem to find the answer
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Use the quadratic formula

Notice that the quadratic 2x%5E2%2B14x%2B4 is in the form of Ax%5E2%2BBx%2BC where A=2, B=14, and C=4


Let's use the quadratic formula to solve for "x":


x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


x+=+%28-%2814%29+%2B-+sqrt%28+%2814%29%5E2-4%282%29%284%29+%29%29%2F%282%282%29%29 Plug in A=2, B=14, and C=4


x+=+%28-14+%2B-+sqrt%28+196-4%282%29%284%29+%29%29%2F%282%282%29%29 Square 14 to get 196.


x+=+%28-14+%2B-+sqrt%28+196-32+%29%29%2F%282%282%29%29 Multiply 4%282%29%284%29 to get 32


x+=+%28-14+%2B-+sqrt%28+164+%29%29%2F%282%282%29%29 Subtract 32 from 196 to get 164


x+=+%28-14+%2B-+sqrt%28+164+%29%29%2F%284%29 Multiply 2 and 2 to get 4.


x+=+%28-14+%2B-+2%2Asqrt%2841%29%29%2F%284%29 Simplify the square root (note: If you need help with simplifying square roots, check out this solver)


x+=+%28-14%2B2%2Asqrt%2841%29%29%2F%284%29 or x+=+%28-14-2%2Asqrt%2841%29%29%2F%284%29 Break up the expression.


x+=+%28-7%2Bsqrt%2841%29%29%2F%282%29 or x+=+%28-7%2Bsqrt%2841%29%29%2F%282%29 Reduce


So the solutions are x+=+%28-7%2Bsqrt%2841%29%29%2F%282%29 or x+=+%28-7%2Bsqrt%2841%29%29%2F%282%29