SOLUTION: The position of an object moving in a straight line is given by s=t^2-8t, where s is in feet and t is the time in seconds the object has been in motion. How long (to the nearest t

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: The position of an object moving in a straight line is given by s=t^2-8t, where s is in feet and t is the time in seconds the object has been in motion. How long (to the nearest t      Log On


   

Question 55366: The position of an object moving in a straight line is given by s=t^2-8t, where s is in feet and t is the time in seconds the object has been in motion. How long (to the nearest tenth) will it take the object to move 10 feet?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
s=t^2-8t
10=t^2-8t
t^2-8t-10=0
Use the quadratic formula to get:
t=[8+-sqrt(64+40)]/2
t=[8+-2sqrt(26)]]2
t=[4+-sqrt26]
t= 9.09 seconds
Cheers,
Stan H.