SOLUTION: What is the equation of the line having slope 4/7 and passing through the point (-3,1) in standard form?

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: What is the equation of the line having slope 4/7 and passing through the point (-3,1) in standard form?      Log On


   



Question 54758: What is the equation of the line having slope 4/7 and passing through the point (-3,1) in standard form?
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
What is the equation of the line having slope 4/7 and passing through the point (-3,1) in standard form?
You are given a slope (m) and a point (x1,y1) and are being asked for the equation of a line, so you need to use the point-slope formula.highlight%28y-y1=m%28x-x1%29%29
The standard form of a line is highlight%28Ax%2BBy=C%29 A,B, and C are integers and in most books A is positive.
:
Your slope(m)=4/7 and your point (x1,y1)=(-3,1)
y-1=%284%2F7%29%28x-%28-3%29%29
y-1=%284%2F7%29%28x%2B3%29
7%28y-1%29=7%284%2F7%29%28x%2B3%29
7y-7=cross%287%29%284%2Fcross%287%29%29%28x%2B3%29
7y-7=4%28x%2B3%29
7y-7=4x%2B12
-4x%2B7y-7=-4x%2B4x%2B12
-4x%2B7y-7%2B7=12%2B7
-4x%2B7y=19
-%28-4x%2B7y%29=-%2819%29
4x-7y=-19
Happy Calculating!!!