SOLUTION: Find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function. f(x)=-4(x+8)^2 +2

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: Find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function. f(x)=-4(x+8)^2 +2      Log On


   

Question 473447: Find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function.
f(x)=-4(x+8)^2 +2
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function.
f(x)=-4(x+8)^2 +2
**
Standard for a parabola: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex. A is a multiplier which affects the steepness of the curve.
For given equation:
f(x)=-4(x+8)^2 +2
This is a parabola with the vertex at (-8,2).
The lead coefficient being negative means the parabola opens downward, and it has a maximum value of 2. The axis of symmetry is y=-8
See the graph below as a visual check on the answers:
..
+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+-4%28x%2B8%29%5E2+%2B2%29+