SOLUTION: What is the type and how many solutions are there to the following quadratic equation? x^2-3x+3=0 A. one rational solution B. two complex solutions C. two rational solutions T

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: What is the type and how many solutions are there to the following quadratic equation? x^2-3x+3=0 A. one rational solution B. two complex solutions C. two rational solutions T      Log On


   



Question 435483: What is the type and how many solutions are there to the following quadratic equation?
x^2-3x+3=0
A. one rational solution
B. two complex solutions
C. two rational solutions
Thanks.

Answer by solver91311(24713) About Me  (Show Source):
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For any quadratic polynomial equation of the form:



Find the Discriminant, and evaluate the nature of the roots as follows:

No calculation quick look: If the signs on and are opposite, then guaranteed.

Two real and unequal roots. If is a perfect square, the quadratic factors over (the rationals).

One real root with a multiplicity of two. That is to say that the trinomial is a perfect square and has two identical factors. Presuming rational coefficients, the root will be rational as well.

A conjugate pair of complex roots of the form where is the imaginary number defined by


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