SOLUTION: solve the quadratic equation 3x squared +4x+2=0 {{{3x^2 + 4x + 2 = 0}}}

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Question 4346: solve the quadratic equation 3x squared +4x+2=0
3x%5E2+%2B+4x+%2B+2+=+0
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
3x%5E2+%2B+4x+%2B+2+=+0
Solving an equation by the quadratic formula is as easy as "a, b, c."
First identify the values of a=3, b=4, c=2. Substitute these values into the quadratic formula:

x+=+%28-b+%2B-sqrt%28b%5E2+-+4%2Aa%2Ac%29%29%2F%282a%29

Substitute the values of a=3, b=4, and c=2:
x+=+%28-4+%2B-sqrt%284%5E2+-+4%2A3%2A2%29%29%2F%282%2A3%29
x+=+%28-4+%2B-sqrt%2816+-+24%29%29%2F%286%29
x+=+%28-4+%2B-sqrt%28-8%29%29%2F%286%29
x+=+%28-4+%2B-sqrt%28-4%29%2A+sqrt+%282%29%29%2F%286%29
x+=+%28-4+%2B-2i%2Asqrt%282%29%29%2F%286%29

To reduce the fraction, it's a good idea to factor the numerator:
x+=+%282%28-2+%2B-i%2Asqrt%282%29%29%29%2F%286%29

Now divide out the 2 factor in the numerator with the 6 in the denominator.
x+=+%28%28-2+%2B-i%2Asqrt%282%29%29%29%2F%283%29
Final answer!

R^2 at SCC