SOLUTION: Find the area and perimeter of an 4 1/2-by-21-inch piece of paper. Area ? square inches Perimeter ? inches Please write down the steps to get the answer. Thanks

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: Find the area and perimeter of an 4 1/2-by-21-inch piece of paper. Area ? square inches Perimeter ? inches Please write down the steps to get the answer. Thanks      Log On


   

Question 427855: Find the area and perimeter of an 4 1/2-by-21-inch piece of paper.
Area ? square inches
Perimeter ? inches
Please write down the steps to get the answer. Thanks
Found 2 solutions by richard1234, josmiceli:
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
Area = length*width = (4 1/2 in)(21 in) = 94 1/2 sq in
Perimeter = 2*length + 2*width = 2(4 1/2 in) + 2(21 in) = 51 in

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The paper is a rectangle
To find area, multiply the sides
+A+=+4.5+%2A+21+
+A+=+94.5+ in2
To find the perimeter, add up the 4 sides
P+=+4.5+%2B+4.5+%2B+21+%2B+21+ in
P+=+51 in
Note that area is in square inches, and
perimeter is in inches