SOLUTION: Identify the maximum or minimum (vertex), zeros, and axis of symmetry line and show the graph. y=-3x^2-6x+5

Hi

Identify the maximum or minimum (vertex), zeros, and axis of symmetry lin

Using the vertex form of a parabola,  where(h,k) is the vertex

 y = -3x^2-6x+5            |Completing the square

 y = -3(x+1)^2 + 8         |Vertex is Pt(-1,8)& a Maximum as Parbola opens downward (a< 0) 

 0 = -3(x+1)^2 + 8     8/3 = (x+1)^2  x = -1 ± 2sqrt(2/3)  {.633, -2.633}