SOLUTION: Identify the maximum or minimum (vertex), zeros, and axis of symmetry line and show the graph. y=x^2-2x-3

Hi

Identify the maximum or minimum (vertex), zeros, and axis of symmetry lin

Using the vertex form of a parabola,  where(h,k) is the vertex

 y = x^2-2x-3            |Completing the square

 y = (x-1)^2 -4        |Vertex is Pt(1,-4)& a Minimum as Parbola opens upward (a> 0) x=1, the line of symmetry

 0 = (x-1)^2 -4      4 = (x-1)^2        x = 1 ± 2  {-1,3}