SOLUTION: Identify the maximum or minimum (vertex), zeros, and axis of symmetry line and show the graph. y=-x^2+2x+3

Hi

Identify the maximum or minimum (vertex), zeros, and axis of symmetry lin

Using the vertex form of a parabola,  where(h,k) is the vertex

 y = -x^2+2x+3            |Completing the square

 y = -(x-1)^2 +4       |Vertex is Pt(1,4)& a Maximum as Parbola opens downward(a> 0)    x = 1, the line of symmetry

 0 = -(x-1)^2 + 4      4 = (x-1)^2        x = 1 ± 2  {-1,3}